|  | 
| 
 
 
| Question 657201:  6 children and 2 men complete a certain peice of work in 6 days ,each child takes twice the time teken by a man to fifnish the work ,in how many days will 6 men ll finish the work?
 Answer by KMST(5328)
      (Show Source): 
You can put this solution on YOUR website! THE FIFTH GRADER SOLUTION: If "each child takes twice the time taken by a man to finish the work", then 2 children do the same work as 1 man, and 6 children would do the work of 3 men.
 Then, 6 children and 2 men would do the same work as 3 men and another 2 men, which adds up to 5 men.
 The amount of work done was 5 men times 6 days or
  man-days. Obviously, 6 men working
  days will also finish the same  man-days job. 
 WHAT THE TEACHER EXPECTS,
 I am not exactly sure, because there are many problem-solving recipe books.
 I do not know what recipe your teacher uses, but I will try my best guess.
 The amount of work done by a person or a group (or some sort of machine, divided by the time worked is the rate of work.
 
  once we know the rate of work, we can calculate work done over a given period of time, or time required to finish a given amount of work
 If one man would take
  days to finish the job by himself, then a child would take  days. A man's rate of work would be
  , in jobs per day. (We could call that the rate of work of a man,
  , in jobs per day, and we would save ourselves from writing so many denominators). A child's rate of work would be
  The rate of work for a group would be found adding the rates for all the members of the group.
 The rate of work for 6 men would be
  . The rate of work for 2 men and 6 children would be
 
  The group of 2 men and 6 children completed 1 job in 6 days, so
 
  job The group of 6 mean would complete the same job in
  days, so 
  Multiplying both sides times
  , which we know is not zero, 
  -->  -->  days.
 | 
  
 | 
 |  |  |