SOLUTION: find two consecutive integers such that twice the first is 26 more than the second

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Question 657048: find two consecutive integers such that twice the first is 26 more than the second
Answer by kevwill(135) About Me  (Show Source):
You can put this solution on YOUR website!
Let x be the first of the two consecutive integers. Then the second is x+1. If twice the first is 26 more than the second, we have:
2x = (x+1) + 26
2x = x + 27
x = 27
The two numbers are 27 and 28.