SOLUTION: Some "x-values" make the denominator of a rational function
undefined. Why can't the graph of that function cross the vertical lines
(vertical asymptotes) that have those values
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-> SOLUTION: Some "x-values" make the denominator of a rational function
undefined. Why can't the graph of that function cross the vertical lines
(vertical asymptotes) that have those values
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Question 6569: Some "x-values" make the denominator of a rational function
undefined. Why can't the graph of that function cross the vertical lines
(vertical asymptotes) that have those values for "x-intercepts"? Answer by longjonsilver(2297) (Show Source):
the x-values that make the function undefined are values that are UNDEFINED, so you cannot have that/those values, so you will never have the curve crossing the asymptote (--> the line denoting the undefined value)
