SOLUTION: evaluate 4^0-8^(2/3)+9^(1/2)

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Question 656434: evaluate 4^0-8^(2/3)+9^(1/2)
Found 2 solutions by Shana-D77, MathTherapy:
Answer by Shana-D77(132) About Me  (Show Source):
You can put this solution on YOUR website!


evaluate 4^0-8^(2/3)+9^(1/2)


Let's break this into a few parts:


First part: 4^0 = 1. All numbers raised ot the zero power are equal to 1. Always. We can go into this more if you want (just email me).


Second part: 8^(2/3)
8^(2/3) = (8^2)(8^(1/3))
8^2 = 64 and
8^(1/3) = 2 [because 2*2*2 = 8],
so 8^(2/3) = 64*2 = 128


Third part: 9^(1/2)
Anything raised to the 1/2 is a square root. 25^(1/2) = 5, for example.
So, 9^(1/2) = 3


Put the pieces together:
0 - 128 + 3 =
-128 + 3 =
-125

Answer by MathTherapy(10551) About Me  (Show Source):
You can put this solution on YOUR website!

evaluate 4^0-8^(2/3)+9^(1/2)

4%5E0+-+8%5E%282%2F3%29+%2B+9%5E%281%2F2%29 ---- 1+-+%28root%283%2C8%29%29%5E2+%2B+sqrt%289%29 ----- 1+-+2%5E2+%2B+3

1 - 4 + 3

highlight_green%280%29

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