SOLUTION: If all men had identical body types their weights would vary directly as the cube of their heights. Robert Wadlow was 8 feet 11 inches tall (107 inches) at the time of his death. I

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: If all men had identical body types their weights would vary directly as the cube of their heights. Robert Wadlow was 8 feet 11 inches tall (107 inches) at the time of his death. I      Log On


   

Question 656242: If all men had identical body types their weights would vary directly as the cube of their heights. Robert Wadlow was 8 feet 11 inches tall (107 inches) at the time of his death. If a man who is 5 feet 10 inches tall (70 inches) with the same body type as Mr Wadlow weighs 170 pounds, what was Mr Wadlows weight?
This is supposed to be a proportion problem and I can't get the equation.
The answer is approximately 607 pounds. Can you help?
Answer by MathTherapy(10555) About Me  (Show Source):
You can put this solution on YOUR website!

If all men had identical body types their weights would vary directly as the cube of their heights. Robert Wadlow was 8 feet 11 inches tall (107 inches) at the time of his death. If a man who is 5 feet 10 inches tall (70 inches) with the same body type as Mr Wadlow weighs 170 pounds, what was Mr Wadlows weight?
This is supposed to be a proportion problem and I can't get the equation.
The answer is approximately 607 pounds. Can you help?

Weight = H%5E3
Let Wadlow’s weight then be W
Then: 170%2FW+=+70%5E3%2F107%5E3, or W%2F107%5E3+=+170%2F70%5E3
70%5E3%28W%29+=+170%28107%5E3%29 ----- Cross-multiplying
W+=+%28170%28107%5E3%29%29%2F70%5E3
W, or Wadlow's weight then = 607.16417 ≈ 607 lbs

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