SOLUTION: Two earthquakes differ by 1.0 when measured on the richter scale. How would the seismographic readings differ at a distance of 100 kilometers from the epicenter? How do their inten
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Question 65623This question is from textbook Algebra & trigonometry
: Two earthquakes differ by 1.0 when measured on the richter scale. How would the seismographic readings differ at a distance of 100 kilometers from the epicenter? How do their intensities compare? This question is from textbook Algebra & trigonometry
You can put this solution on YOUR website! Two earthquakes differ by 1.0 when measured on the richter scale. How would the seismographic readings differ at a distance of 100 kilometers from the epicenter? How do their intensities compare?
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Assume one of the earthquakes has magnitude M and the other has magnitude M+1.
Then M=10log(P/Po) where Po is the minimum detectable earthquake power.
Then M/10= log(P/Po)
Then P/Po=10^(M/10)
And P=Po[10^(M/10)]
Note: P is the Power of the earthquake whose Ricter measurement is M.
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For the 2nd earthquake:
M+1=10log(P/Po)
(M+1)/10=log(P/Po)
P/Po=10^[(M/10)+1/10]
P=Po[10^(M/10}*(10^(1/10)
P=Po[10^(M/10)]*1.25
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So the 2nd earthquake is 1.25 times as powerful as the 1st.
That means the 2nd is 25% stronger than the 1st.
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Cheers,
Stan H.