SOLUTION: 1. Find the correlation coefficient for the data.
2. Find the equation for the regression line for the data, and predict the final grade of a student who misses 3.5 days.
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-> SOLUTION: 1. Find the correlation coefficient for the data.
2. Find the equation for the regression line for the data, and predict the final grade of a student who misses 3.5 days.
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Question 656178: 1. Find the correlation coefficient for the data.
2. Find the equation for the regression line for the data, and predict the final grade of a student who misses 3.5 days.
Number of Absences ....... Final Grade
0 ....................... 100
1 ....................... 92
2 ....................... 83
3 ....................... 78
4 ....................... 66
5 ....................... 51
I don't know where to begin, I am running out of time. I hope someone can help! Answer by ewatrrr(24785) (Show Source):
Hi,
Don't know what You have been using to determine standard deviationetc in general:
If you have a TI 83 calculator,might recommend this tutorial site:
http://www.tc3.edu/instruct/sbrown/ti83/regress.htm where
s[x]= sqrt and s[y] = sqrt
and
In the normal Work Up using an Excel Worksheet, there is a need to sum (xi - 2.5)(yi - 78.2) as well
(xi-2.5)^2 (yi-78.2)^2 (xi-2.5)(yi-78.2)
6.25 475.24 -54.5
2.25 190.44 -20.7
0.25 14.44 -1.9
0.25 0.04 -0.1
2.25 148.84 -18.3
6.25 739.84 -68
Sum 17.5 1568.84 -163.5
33.14 = -32.7/33.14 = -.9867
Regression Line 1s: y = ax + b, where
a =
and
a = -163.5/17.5 = -9.34 = 100.5
y = -9.34x + 100.5
