SOLUTION: solving by elimination 5x-7y=-49 3x+9y=-3

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Question 656140: solving by elimination
5x-7y=-49
3x+9y=-3

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

Solved by pluggable solver: Solving a System of Linear Equations by Elimination/Addition


Lets start with the given system of linear equations

5%2Ax-7%2Ay=-49
3%2Ax%2B9%2Ay=-3

In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for y, we would have to eliminate x (or vice versa).

So lets eliminate x. In order to do that, we need to have both x coefficients that are equal but have opposite signs (for instance 2 and -2 are equal but have opposite signs). This way they will add to zero.

So to make the x coefficients equal but opposite, we need to multiply both x coefficients by some number to get them to an equal number. So if we wanted to get 5 and 3 to some equal number, we could try to get them to the LCM.

Since the LCM of 5 and 3 is 15, we need to multiply both sides of the top equation by 3 and multiply both sides of the bottom equation by -5 like this:

3%2A%285%2Ax-7%2Ay%29=%28-49%29%2A3 Multiply the top equation (both sides) by 3
-5%2A%283%2Ax%2B9%2Ay%29=%28-3%29%2A-5 Multiply the bottom equation (both sides) by -5


So after multiplying we get this:
15%2Ax-21%2Ay=-147
-15%2Ax-45%2Ay=15

Notice how 15 and -15 add to zero (ie 15%2B-15=0)


Now add the equations together. In order to add 2 equations, group like terms and combine them
%2815%2Ax-15%2Ax%29-21%2Ay-45%2Ay%29=-147%2B15

%2815-15%29%2Ax-21-45%29y=-147%2B15

cross%2815%2B-15%29%2Ax%2B%28-21-45%29%2Ay=-147%2B15 Notice the x coefficients add to zero and cancel out. This means we've eliminated x altogether.



So after adding and canceling out the x terms we're left with:

-66%2Ay=-132

y=-132%2F-66 Divide both sides by -66 to solve for y



y=2 Reduce


Now plug this answer into the top equation 5%2Ax-7%2Ay=-49 to solve for x

5%2Ax-7%282%29=-49 Plug in y=2


5%2Ax-14=-49 Multiply



5%2Ax=-49%2B14 Subtract -14 from both sides

5%2Ax=-35 Combine the terms on the right side

cross%28%281%2F5%29%285%29%29%2Ax=%28-35%29%281%2F5%29 Multiply both sides by 1%2F5. This will cancel out 5 on the left side.


x=-7 Multiply the terms on the right side


So our answer is

x=-7, y=2

which also looks like

(-7, 2)

Notice if we graph the equations (if you need help with graphing, check out this solver)

5%2Ax-7%2Ay=-49
3%2Ax%2B9%2Ay=-3

we get



graph of 5%2Ax-7%2Ay=-49 (red) 3%2Ax%2B9%2Ay=-3 (green) (hint: you may have to solve for y to graph these) and the intersection of the lines (blue circle).


and we can see that the two equations intersect at (-7,2). This verifies our answer.