SOLUTION: A piece of work can be done by Beejay in 4 days, by Ryan in 7 days, and by Buds in 10 days. If the three work together, how long will it take them to do the job?
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-> SOLUTION: A piece of work can be done by Beejay in 4 days, by Ryan in 7 days, and by Buds in 10 days. If the three work together, how long will it take them to do the job?
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Question 656105: A piece of work can be done by Beejay in 4 days, by Ryan in 7 days, and by Buds in 10 days. If the three work together, how long will it take them to do the job? Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! A piece of work can be done by Beejay in 4 days, by Ryan in 7 days, and by Buds in 10 days. If the three work together, how long will it take them to do the job?
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Let x = time (days) it takes for all three
then
x(1/4 + 1/7 + 1/10) = 1
multiplying both sides by 140:
x(140/4 + 140/7 + 140/10) = 140
x(35 + 20 + 14) = 140
x(69) = 140
x = 140/69
x = 2.029 days
or
x = 2 days and 0.7 hours
or
x = 2 days and 42 minutes
