SOLUTION: I am having trouble trying to express this equation in Logarithmic form: e^(x+2)=0.2 Can you please help me?

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Question 655985: I am having trouble trying to express this equation in Logarithmic form:






e^(x+2)=0.2






Can you please help me?
Found 2 solutions by Alan3354, MathDazed:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
e^(x+2)=0.2
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Get the log of both sides.
x+2 = ln(0.2)

Answer by MathDazed(34) About Me  (Show Source):
You can put this solution on YOUR website!
(X+2)ln e = ln 0.2
Ln e = 1


X+2 = ln 0.2


X = ln 0.2 - 2


Then solve for x.