SOLUTION: Hi. I have a problem with a rectangle being placed under the parabolic arch given by f(x)=27-3x^2 by using a point (x,y) on the parabola. Write a formula for the function A(x

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Question 65568: Hi.
I have a problem with a rectangle being placed under the parabolic arch given by f(x)=27-3x^2 by using a point (x,y) on the parabola. Write a formula for the function A(x) that gives the area of the rectangle as a function of the x coordinate of the point chosen.
Can anyone help?
Answer by venugopalramana(3286) (Show Source):
You can put this solution on YOUR website!
Hi.
I have a problem with a rectangle being placed under the parabolic arch given by f(x)=27-3x^2 by using a point (x,y) on the parabola. Write a formula for the function A(x) that gives the area of the rectangle as a function of the x coordinate of the point chosen.
Can anyone help?
QUESTION ISLACKING IN CLARITY.IF YOU FIX ONE POINT ON THE PARABOLA BY ITS X COORDINATE EQUAL TO H(SAY 2) THEN SINCE THE PARABOLA IS SYMMETRIC BOUT X=0 OR Y AXIS,-H (-2) IS ALSO A POINT ON THE PARABOLA AND THE RECTANGLE.
SO LENGTH =2H
BUT THEN WHAT IS THE WIDTH?.IF WE TRY TO TAKE ANOTHE POINT ON PARABOLA,IT WILL NOT BE A RECTANGLE BUT TRAPEZIUM.BUT THEN WHAT WIDTH IS TO BE CHOSEN?
IF NOT WE CAN TAKE A SQUARE.
THEN TS AREA IS 2H*2H=4H^2 IS HE AREA OF A SQUARE UNDER THE PARABOLIC ARCH WITH 2 POINTS ON IT.SEE GRAPH BELOW