SOLUTION: X+4y-3z=-8, 3x-y+3z=12, x+y+6z=1 how to solve Cramer's rule ?

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Question 655566: X+4y-3z=-8, 3x-y+3z=12, x+y+6z=1 how to solve Cramer's rule ?
Answer by sravancv(7) About Me  (Show Source):
You can put this solution on YOUR website!

№ X1 X2 X3 b
1 1 4 -3 -8
2 3 -1 3 12
3 1 1 6 1
Write down the main matrix and find its determinant

№ X1 X2 X3
1 1 4 -3
2 3 -1 3
3 1 1 6
D=-81
Replace the 1st column of the main matrix with the solution vector and find its determinant
№ X1 X2 X3
1 -8 4 -3
2 12 -1 3
3 1 1 6
D1=-243
Replace the 2nd column of the main matrix with the solution vector and find its determinant
№ X1 X2 X3
1 1 -8 -3
2 3 12 3
3 1 1 6
D2=216
Replace the 3rd column of the main matrix with the solution vector and find its determinant
№ X1 X2 X3
1 1 4 -8
2 3 -1 12
3 1 1 1
D3=-9
Solution set:
x1 = D1 / D = -243 / (-81) = 3
x2 = D2 / D = 216 / (-81) = -8/3
x3 = D3 / D = -9 / (-81) = 1/9