Question 65554: x+y=5
x+2z=6
y+3z=4
Please solve this system of equations
Answer by chitra(359)  (Show Source):
You can put this solution on YOUR website! THE GIVEN SYSTEM OF EQUATIONS ARE:
X + Y = 5 ------------> (1)
X + 2Z = 6 ------------> (2)
Y + 3Z = 4 ------------> (3)
ADDING (1) AND (3), WE GET:
X + 2Y + 3Z = 9 ---------->(4)
ADDING (2) AND (3), WE GET:
X + Y + 5Z = 10 ---------->(5)
SUBTRACTING (4) AND (5), WE GET:
Y - 2Z = -1 ----------->(6)
SUBTRACTING (6) FROM (3), WE GET:
-5Z = - 5
THIS IMPLIES Z = 1
SUBSTITUTE THE VALUE OF Z IN (6), WE GET:
Y - 2(1) = -1
Y = -1 + 2
Y = 1
NOW, SUBSTITUTE THE VALUE OF Y IN (1), WE GET:
X + 1 = 5
X = 5 - 1
X = 4
HENCE, THE VALUES OF X, Y AND Z ARE:
X = 4, Y = 1 AND Z = 1
HENCE THE SOLUTION.
HAPPY CALCULATING........!!!!!!!!
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