SOLUTION: Find two integers whose product is 100 such that one of the integers is three less than seven times the other integer.

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Question 655125: Find two integers whose product is 100 such that one of the integers is three less than seven times the other integer.
Answer by checkley79(3341) About Me  (Show Source):
You can put this solution on YOUR website!
X*Y=100
X=7Y-3
(7Y-3)Y=100
7Y^2-3Y-100=0
(7Y+25)(Y-4)=0
7Y+25-0
7Y=25/7 ANS.
Y-4=0
Y=4 ANS.
X*4=100
X=100/4
X=25 ANS.
PROOF:
25=7*4-3
25=28-3
25=25