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Question 65502: 5/x-2-5/x^2-4=1/x+2
Answer by checkley71(8403)   (Show Source):
You can put this solution on YOUR website! 5/x-2-5/x^2-4=1/x+2
5/x-1/x-5/x^2=2+2+4
4/x-5/x^2=8 find a common denominator for the /x &/x^2 terms (x^2) & add
(4x-5)/x^2=8 now cross multiply
8x^2=4x-5
8x^2-4x+5=0
using the quadratic equation we solve for x thus
x=(-b+-sqrt[b^2-4ac])/2a
x=(4+-sqrt[-4^2-4*8*5])/2*8
x=(4+-sqrt[16-160])/16
x=(4+-sqrt-144])/16
x=(4+-12i)/16
x=4/16+12i/16
x=.25+.75i solution
x=(4-12i)/16
x=4/16-12i/16
x=.25-.75i solution
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MERRY CHRISTMAS
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