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Question 654902: Write the equation of a line that passes through the point (10,3) and is perpendicular to a line containing the points (-5,-2) and (-3,8) in slope intercept form.
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! Write the equation of a line that passes through the point (10,3) and is perpendicular to a line containing the points (-5,-2) and (-3,8) in slope intercept form.
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Equation of a line: y=mx+b, m=slope, b=y-intercept
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For line containing the points (-5,-2) and (-3,8):
Slope=∆y/∆x=(8-(-2))/(-3-(-5))=10/2=5
equation: y=5x+b
-2=5*-5+b
b=-2+25=23
equation: y=5x+23
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For perpendicular line that passes through the point (10,3)
Slope=-1/5 (negative reciprocal of slope of first line
Equation: y=-x/5+b
solve for b using coordinates of given point (10,3)
3=-10/5+b
3=-2+b
b=5
Equation of perpendicular line:
y=-x/5+5
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