SOLUTION: Well I'm having problems with these types of equations "The figure shows the graphs of f(x)=x^3 and g(x)=ax^3. What can you conclude about the value of a?"

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Well I'm having problems with these types of equations "The figure shows the graphs of f(x)=x^3 and g(x)=ax^3. What can you conclude about the value of a?"       Log On


   

Question 65469: Well I'm having problems with these types of equations
"The figure shows the graphs of f(x)=x^3 and g(x)=ax^3. What can you conclude about the value of a?"

Answer by 303795(602) About Me  (Show Source):
You can put this solution on YOUR website!
+graph%28+300%2C+200%2C+-3%2C+3%2C+-30%2C+30%2C+x%5E3%2C+0%29+
If a=0 then the graph will be a straight line on the x axis.
+graph%28+300%2C+200%2C+-3%2C+3%2C+-30%2C+30%2C+x%5E3%2C+0.5x%5E3%29+
If a is between 0 and 1 then the graph will be between the x axis and the original graph.
+graph%28+300%2C+200%2C+-3%2C+3%2C+-30%2C+30%2C+x%5E3%2C+2x%5E3%29+
If a>1 then the graph will be steeper than the original one.
+graph%28+300%2C+200%2C+-3%2C+3%2C+-30%2C+30%2C+x%5E3%2C+-x%5E3%29+
If a=-1 then a mirror image about the x axis will result.
+graph%28+300%2C+200%2C+-3%2C+3%2C+-30%2C+30%2C+x%5E3%2C+-0.2x%5E3%29+
If a is between 0 and -1 the the graph will be between the x axis and a mirror image of the original graph.
+graph%28+300%2C+200%2C+-3%2C+3%2C+-30%2C+30%2C+x%5E3%2C+-5x%5E3%29+
If a<-1 then the graph will be steeper than a mirror image of the original one.