SOLUTION: In 2010 general admission to the Art Institute cost $18 adults and $12 for children. If $22,752 was collected from the sale of 1460 tickets, how many were adult and how many child

Algebra ->  Customizable Word Problem Solvers  -> Finance -> SOLUTION: In 2010 general admission to the Art Institute cost $18 adults and $12 for children. If $22,752 was collected from the sale of 1460 tickets, how many were adult and how many child      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 654593: In 2010 general admission to the Art Institute cost $18 adults and $12 for children. If $22,752 was collected from the sale of 1460 tickets, how many were adult and how many children tickets?
Answer by checkley79(3341) About Me  (Show Source):
You can put this solution on YOUR website!
A+C=1460
OR
C=1460-A
18A+12C=22752
18A+12(1460-A)=22752
18A+17520-12A=22752
6A=22752-17520
6A=5232
A=5232/6
A=872 ANS. FOR THE NUMBER OF ADULTS.
872+C=1460
C=1460-872
C=588 ANS. FOR THE NUMBER OF CHILDREN TICKETS.
PROOF:
18*872+12*588=22752
15696+7056=22752
22752=22752