SOLUTION: I am really stuck on how to answer this question, it says solve the following equation.. {{{ e^(x)=2e^(1-2x) }}}
I have already tried making the eqaution equal to 0 and trying t
Algebra ->
Exponential-and-logarithmic-functions
-> SOLUTION: I am really stuck on how to answer this question, it says solve the following equation.. {{{ e^(x)=2e^(1-2x) }}}
I have already tried making the eqaution equal to 0 and trying t
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Question 654518: I am really stuck on how to answer this question, it says solve the following equation..
I have already tried making the eqaution equal to 0 and trying to solve it, but i don't know how to, i also tried logging both sides but im not sure how to as both sides contain x and both have powers.
Thankyou Answer by Edwin McCravy(20056) (Show Source):
Divide both sides by =
Subtract exponents of e on the left, cancel on the right:
= = 2
= 2
Use the principle that equation is equivalent to the
equation A = ln(B) to rewrite the above as
3x - 1 = ln(2)
3x = 1 + ln(2)
x =
x ≈ 0.5643823935
Edwin
