SOLUTION: Find the remaining trigonometric ratios. cos(x) = &#8722; 1/7, &#960; < x < 3&#960;/2

Algebra ->  Trigonometry-basics -> SOLUTION: Find the remaining trigonometric ratios. cos(x) = &#8722; 1/7, &#960; < x < 3&#960;/2       Log On


   



Question 654208: Find the remaining trigonometric ratios.
cos(x) = − 1/7, π < x < 3π/2

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Find the remaining trigonometric ratios.
cos(x) = − 1/7, π < x < 3π/2
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you are working with a reference angle and right triangle in quadrant III
cos=-1/7=adj side/hypotenuse
opp side=-√(7^2-1^2)=-√(49-1)=-√48
..
trigonometric ratios:
sin(x)=-√48/7
cos(x)=-1/7
tan(x)=√48
csc(x)=-7/√48
sec(x)=-7
cot(x)=1/√48