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Question 65410: it takes doug 6 days to roof a house. if his son helps him,the job can be done in 4 days. how long would it take his son ,working alone,to roof a house?
Found 2 solutions by chitra, Edwin McCravy: Answer by chitra(359) (Show Source): Answer by Edwin McCravy(20054) (Show Source):
You can put this solution on YOUR website! it takes Doug 6 days to roof a house.
if his son helps him,the job can be done in
4 days. how long would it take his son,
working alone, to roof a house?
>>...it takes Doug 6 days to roof a house...<<
Therefore in ONE day, Doug roofs 1/6 of a house.
>>...if his son helps him,the job can be done
in 4 days...<<
Therefore in 1 day, both working together, they
can roof 1/4 of a house.
Since we know that in that ONE day when both of them
worked, Doug roofed 1/6 of a house that day.
So in that ONE day his son roofed the rest of that
1/4 of a house, So we should subtract to find what
fraction of a house his son roofed that ONE day.
So the son roofed 1/4 - 1/6 of a house in that ONE day.
Subtracting 1/4 - 1/6 = 3/12 - 2/12 = 1/12.
So the son roofed 1/12 of a house that ONE day, so
working alone, it would take him 12 days, roofing
1/12 of it every day.
Look, ma, no algebra, just subtraction of numerical
fractions! :-)
Edwin
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