SOLUTION: (4a^3b^-3c^2)^3/(-2a^-2b^2c^-1)^4
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Question 65396
:
(4a^3b^-3c^2)^3/(-2a^-2b^2c^-1)^4
Answer by
funmath(2933)
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(4a^3b^-3c^2)^3/(-2a^-2b^2c^-1)^4
Happy Calculating!!!