You can put this solution on YOUR website! find asub 1 for each geometric series described
1. S(n)= 45/8; r=1/2 ; n=4
S(4)=a(1)[(1/2)^(4+1)-1]/[(1/2)-1]=45/8
a(1)[1/32-1]/[-1/2]=45/8
a(1)[-31/32/-1/2]=45/8
a(1)[31/16]=45/8
a(1)=90/31
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2. Subn=-242 r=3 n=5
Follow the same pattern as in #1
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Cheers,
Stan H.