SOLUTION: Write each expression in simplest form: I believe I follow the same factoring for fractions which shows: 4*1*x and 4*2*4 5*1*x and 5*7 This would leave me: 4 and 4*2*4 5

Algebra ->  Expressions -> SOLUTION: Write each expression in simplest form: I believe I follow the same factoring for fractions which shows: 4*1*x and 4*2*4 5*1*x and 5*7 This would leave me: 4 and 4*2*4 5      Log On


   



Question 65374This question is from textbook Beginning Algebra
: Write each expression in simplest form:
I believe I follow the same factoring for fractions which shows:
4*1*x and 4*2*4
5*1*x and 5*7
This would leave me:
4 and 4*2*4
5 and 5*7
giving me the answer of:
4(4*2*4)
--------
5(5*7)
Is this correct?
This question is from textbook Beginning Algebra

Answer by 303795(602) About Me  (Show Source):
You can put this solution on YOUR website!
Note : 4*2*4 is not equal to 28.
The factors are the terms which multiply together to give the required expression.
To get the factors of 4x - 28 look for a common factor in each term. You should notice that 4 will go into both 4x and 28. You can therefore write down 4 as one of the factors. You now check what 4 will need to be multiplied by to give 4x + 28. To get the 4x you need to multiply by x and to get -28 you need to multiply by -7. The two factors are therefore 4 and (x-7)

In a similar way you should be able to see that 5 is a common factor in both 5x and 35. Now consider what does 5 need to be multiplied by to get 5x - 35. Hopefully you can work out that the two factors are 5 and (x-7).
So the original problem can be rewritten as
%284x-28%29%2F%285x-35%29
%284%28x-7%29%29%2F%285%28x-7%29%29
The common factor of (x-7) can now be cancelled out
%284cross%28%28x-7%29%29%29%2F%285cross%28%28x-7%29%29%29
4%2F5