SOLUTION: This is the problem: How many ounces of 50% antifreeze solution must be mixed with 10oz of an 80% antifreeze solution to produce a 60% antifreeze solution. I'm supposed to make

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Question 653649: This is the problem: How many ounces of 50% antifreeze solution must be mixed with 10oz of an 80% antifreeze solution to produce a 60% antifreeze solution.
I'm supposed to make an equation for it and solve and I have no idea how to do so.

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +x+ = oz of 50% antifreeze solution needed
+.5x+ = oz of antifreeze in 50% antifreeze solution
+.8%2A10+=+8+ oz of antifreeze in 80% antifreeze solution
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+%28+.5x+%2B+8+%29+%2F+%28+x+%2B+10+%29+=+.6+
+.5x+%2B+8+=+.6%2A%28+x+%2B+10+%29+
+.5x+%2B+8+=+.6x+%2B+6+
+.1x+=+2+
+x+=+20+
20 oz of 50% antifreeze solution is needed
check answer:
+%28+.5%2A20+%2B+8+%29+%2F+%28+20+%2B+10+%29+=+.6+
+%28+10+%2B+8+%29+%2F+30+=+.6+
+18%2F30+=+.6+
+18+=+.6%2A30+
+18+=+18+
OK