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Question 65343: divide (a^3-5a^2+13x-14)/(a-2)
Answer by Edwin McCravy(20060) (Show Source):
You can put this solution on YOUR website! divide (a^3-5a^2+13a-14)/(a-2)
Start out with this:
`
a - 2 )a³ - 5a² + 13a - 14
The "a" goes into the "a²" "a" times, so write "a" over the "- 5a²"
a² `
a - 2 )a³ - 5a² + 13a - 14
Now multiply the a² by the -2 and get -2a² and write that below the
"- 5a²":
a² `
a - 2 )a³ - 5a² + 13a - 14
- 2a²
Now multiply the a² by the a, getting a³, so write that under the
a³.
a² `
a - 2 )a³ - 5a² + 13a - 14
a² - 2a²
Now draw a line and subtract (-5a²)-(-2a²) = -5a²+2a² = -3a². So write that under
the - 2a² termm, and bring down the next term, " 13a"
a² `
a - 2 )a³ - 5a² + 13a - 14
a² - 2a²
- 3a² + 13a
"a" goes into "-3a²" "-3a" times. So we write "- 3a" above the "+ 13a"
a² - 3a `
a - 2 )a³ - 5a² + 13a - 14
a² - 2a²
- 3a² + 13a
Now multiply the -3a by both the a and the -2, getting -3a² + 6a. Write
that at the bottom.
a² - 3a `
a - 2 )a³ - 5a² + 13a - 14
a² - 2a²
- 3a² + 13a
-3a² + 6a
Draw a line and subtract: (+ 13a) - (+ 6a) = 13a - 6a = 7a.
So write 7a under the 6a. Bring down the last term "-14"
a² - 3a `
a - 2 )a³ - 5a² + 13a - 14
a² - 2a²
- 3a² + 13a
-3a² + 6a
7a - 14
"a" goes into "7a" "7" times, so write "+ 7" above the "- 14"
a² - 3a + 7
a - 2 )a³ - 5a² + 13a - 14
a² - 2a²
- 3a² + 13a
-3a² + 6a
7a - 14
Multiply the "+ 7" by both the "a" and the "- 2", and get "7a - 14", so
write this at the bottom
a² - 3a + 7
a - 2 )a³ - 5a² + 13a - 14
a² - 2a²
- 3a² + 13a
-3a² + 6a
7a - 14
7a - 14
Draw a line and subtract: (-14) - (-14) = -14 + 14 = 0
Write 0 at the bottom under the -14
a² - 3a + 7
a - 2 )a³ - 5a² + 13a - 14
a² - 2a²
- 3a² + 13a
-3a² + 6a
7a - 14
7a - 14
0
Since the remainder is 0, the answer is a² - 3a + 7 that you
see at the top.
Edwin
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