SOLUTION: What are the coordinates of the vertex of y=-x^2

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Question 653339: What are the coordinates of the vertex of y=-x^2
Found 2 solutions by stanbon, MathLover1:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
What are the coordinates of the vertex of y=-x^2
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Vertex Form:
y-0 = -(x-0^2
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Vertex: (0,0)
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Cheers,
Stan H.

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

since you have y=-x%5E2, in standard form y=ax%5E2%2Bbx%2Bc
The x-value of the vertex can be found using the formula h=-b%2F2a
since a=-1 and b=0, we will have
h=-0%2F2%28-1%29
highlight%28h=0%29
now, use vertex form to find k
y=a%28x-h%29%5E2%2Bk...as you can see, when you compare to your equation, k=0
so, vertex will be at (0,0)
let's see it on a graph:
+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C+-x%5E2%29+