SOLUTION: I need to graph and solve each system 8x-3y=-3 4x-2y=-4

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Question 652969: I need to graph and solve each system
8x-3y=-3
4x-2y=-4
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

Solved by pluggable solver: Solve the System of Equations by Graphing



Start with the given system of equations:


8x-3y=-3

4x-2y=-4





In order to graph these equations, we need to solve for y for each equation.




So let's solve for y on the first equation


8x-3y=-3 Start with the given equation



-3y=-3-8x Subtract 8+x from both sides



-3y=-8x-3 Rearrange the equation



y=%28-8x-3%29%2F%28-3%29 Divide both sides by -3



y=%28-8%2F-3%29x%2B%28-3%29%2F%28-3%29 Break up the fraction



y=%288%2F3%29x%2B1 Reduce



Now lets graph y=%288%2F3%29x%2B1 (note: if you need help with graphing, check out this solver)



+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C+%288%2F3%29x%2B1%29+ Graph of y=%288%2F3%29x%2B1




So let's solve for y on the second equation


4x-2y=-4 Start with the given equation



-2y=-4-4x Subtract 4+x from both sides



-2y=-4x-4 Rearrange the equation



y=%28-4x-4%29%2F%28-2%29 Divide both sides by -2



y=%28-4%2F-2%29x%2B%28-4%29%2F%28-2%29 Break up the fraction



y=2x%2B2 Reduce





Now lets add the graph of y=2x%2B2 to our first plot to get:


+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C+%288%2F3%29x%2B1%2C2x%2B2%29+ Graph of y=%288%2F3%29x%2B1(red) and y=2x%2B2(green)


From the graph, we can see that the two lines intersect at the point (3%2F2,5) (note: you might have to adjust the window to see the intersection)