Question 652552: If 9 is subtracted from the sum of two consecutive even integers, the result is 3 more than the larger of the integers. Find the integer.
Found 2 solutions by Shana-D77, MathTherapy:
Answer by Shana-D77(132)   (Show Source):
You can put this solution on YOUR website! let x = first, smaller, integer
let x + 1 = next, larger, consecutive integer (this is always true)
"sum of two consecutive integers":
x + (x + 1) or
2x + 1 simplified.
"if 9 is subtracted from it..."
2x + 1 - 9 or
2x - 8 simplified.
"The result is(=) 3 more than the larger of the integers"
= (x + 1) + 3
so,
2x - 8 = (x + 1) + 3
2x - 8 = x + 4
x - 8 = 4 (subtracted x from both sides)
x = 12 (added 8 to both sides)
If x = 12, then the next number is 13.
12, 13
Answer by MathTherapy(10555)  (Show Source):
You can put this solution on YOUR website!
If 9 is subtracted from the sum of two consecutive even integers, the result is 3 more than the larger of the integers. Find the integer.
The two consecutive even integers are: 
Send comments and “thank-yous” to “D” at MathMadEzy@aol.com
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