You can put this solution on YOUR website! find sin theta if cos theta = 5/13 and theta terminates in QI
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cos = x/r, so x = 5 and r = 13
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Solve for "y":
y^2 = r^2-x^2
y = sqrt[13^2-5^2) = sqrt[169-25] = sqrt(144) = 12
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Ans: sin = y/r = 12/13
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Cheers,
Stan H.