SOLUTION: The length of a rectangle is 9 inches more than thr width. The perimeter is 54 inches. Find the length and width of the rectangle

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Question 651881: The length of a rectangle is 9 inches more than thr width. The perimeter is 54 inches. Find the length and width of the rectangle
Found 2 solutions by rfer, MathLover1:
Answer by rfer(16322) About Me  (Show Source):
You can put this solution on YOUR website!
54=2(x+9)+2x

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

The length L of a rectangle is 9+in more than thr? width W.
L=W%2B9in.....1
The perimeter P is 54in.
P=2%28L%2BW%29....2
54in=2%28L%2BW%29...plug in L from 1
54in=2%28W%2B9in%2BW%29...solve for W
54in%2F2=W%2B9in%2BW
27in=2W%2B9in
27in-9in=2W
18in=2W
18in%2F2=W
highlight%289in=W%29
now find
L=W%2B9in.....1
L=9in%2B9in
highlight%28L=18in%29