SOLUTION: jennifer has nickels, dims and quarters in her piggy bank. in total she has 49 coins, with a value of $5.20. if she has five more dimes than all the nickels and quarters combined,

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: jennifer has nickels, dims and quarters in her piggy bank. in total she has 49 coins, with a value of $5.20. if she has five more dimes than all the nickels and quarters combined,       Log On


   

Question 651706: jennifer has nickels, dims and quarters in her piggy bank. in total she has 49 coins, with a value of $5.20. if she has five more dimes than all the nickels and quarters combined, how many of each type of coin does she have?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

49 coins...

five more dimeshighlight%28d%29 than all the nickelshighlight%28n%29 and quartershighlight%28q%29 combined

 q + n + d = 49      || d+=+%28q%2Bn%29%2B5

 q + n + ((q+n)+5) = 49

       2q + 2n = 44

        q + n = 22   0r n+=+%2822-q%29  And... the number of dimes = 27  

Question states*** value of $5.20

CENTS makes sense

 25q + 10d + 5n = 520

 25q + 10·27 + 5(22-q) = 520

 25q + 10·27 + 5·22- 5q = 520

                20q = 140

                  q = 7, the number of quaters.  Number of Nickels = 15

and...

25%2A7+%2B+10%2A27+%2B+5%2A15+=+520