SOLUTION: please take me step by step for this and how it is done . please, i don't know the rules for either of these
1.)solve 2x+3x-5+7=10x+3-6x-4
2.)solve 7=-5(2a-1)-(-11a+6)
I know
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Distributive-associative-commutative-properties
-> SOLUTION: please take me step by step for this and how it is done . please, i don't know the rules for either of these
1.)solve 2x+3x-5+7=10x+3-6x-4
2.)solve 7=-5(2a-1)-(-11a+6)
I know
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Question 651695: please take me step by step for this and how it is done . please, i don't know the rules for either of these
1.)solve 2x+3x-5+7=10x+3-6x-4
2.)solve 7=-5(2a-1)-(-11a+6)
I know you have to eliminate the parentheses from #2, I'm just so confused about the steps. Answer by ewatrrr(24785) (Show Source):
Hi,
the idea is to take the steps necessary so that the is isolated on one side of the EQ
2x+3x-5+7=10x+3-6x-4 ||combine Like Terms on each side of EQ
5x + 2 = 4x - 1 || combine Like Terms from BOTH sides of the EQ
5x+ 2 - 4x - 2 = 4x-1 - 4x -2
x = -3 ||Note: when x has been isolated, the we can Read x = -3 !
7=-5(2a-1)-(-11a+6) ||"eliminate the parentheses" Yes!
7 = -10a + 5 +11a - 6 ||combine Like Terms on each side of EQ
7 = a - 1 || combine Like Terms from BOTH sides of the EQ
8 = a
