SOLUTION: find three consecutive even integers so that first plus twice the second is twice the third

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Question 651329: find three consecutive even integers so that first plus twice the second is twice the third
Answer by nerdybill(7384) About Me  (Show Source):
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find three consecutive even integers so that first plus twice the second is twice the third
.
Let x = first of three consecutive even integers
then
x+2 = second
x+4 = third
.
x + 2(x+2) = 2(x+4)
x + 2x+4 = 2x+8
3x+4 = 2x+8
3x = 2x+4
x = 4 (first)
.
second:
x+2 = 4+2 = 6
.
third:
x+4 = 4+4 = 8
.
answer: 4, 6, and 8