SOLUTION: We drove from town A to town D. In order to get there, we hade to drive thru town B and town C. It is 10 mi farther from town A to town B then it is from town B to town C. It is 10

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: We drove from town A to town D. In order to get there, we hade to drive thru town B and town C. It is 10 mi farther from town A to town B then it is from town B to town C. It is 10      Log On

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Question 651286: We drove from town A to town D. In order to get there, we hade to drive thru town B and town C. It is 10 mi farther from town A to town B then it is from town B to town C. It is 10mi farther from town B to town C then it from town C to town D. It is 330 miles from town A to town D. How far is it from town A to town B?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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We drove from town A to town D. In order to get there, we had to drive thru
town B and town C.
It is 10 mi farther from town A to town B than it is from town B to town C.
It is 10mi farther from town B to town C than it from town C to town D.
It is 330 miles from town A to town D.
How far is it from town A to town B?
:
A--------------B---------C------D
:
"It is 10 mi farther from town A to town B than it is from town B to town C."
AB = BC + 10
:
"It is 10mi farther from town B to town C than it from town C to town D."
BC = DC + 10
or
DC = BC - 10
:
"It is 330 miles from town A to town D.
AD = 330
Therefore
AB + BC + CD = 330
replace AB and DC
(BC+10) + BC + (BC-10) = 330
Combine like terms
3BC + 10 - 10 = 330
3BC = 330
BC = 330/3
BC = 110
:
"How far is it from town A to town B?"
AB = BC + 10
AB = 110 + 10
AB = 120 mi