SOLUTION: the question asks to solve for x, and i'm stuck on it {{{9*5^x=17*2^x}}}

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: the question asks to solve for x, and i'm stuck on it {{{9*5^x=17*2^x}}}      Log On


   



Question 651269: the question asks to solve for x, and i'm stuck on it
9%2A5%5Ex=17%2A2%5Ex

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
solve for x
9*5^x=17*2^x
take log of both sides
log9+xlog5=log17+xlog2
xlog5-xlog2=log17-log9
x(log5-log2)=(log17-log9)
x=(log17-log9)/(log5-log2)
x≈.6941