SOLUTION: George can paint a room alone in six hours. Ed can paint the same room alone in eight hours. George starts painting at 10:00 A.M. Ed joins George at 11:00 A.M. and the two men cont

Algebra ->  Rate-of-work-word-problems -> SOLUTION: George can paint a room alone in six hours. Ed can paint the same room alone in eight hours. George starts painting at 10:00 A.M. Ed joins George at 11:00 A.M. and the two men cont      Log On


   



Question 651259: George can paint a room alone in six hours. Ed can paint the same room alone in eight hours. George starts painting at 10:00 A.M. Ed joins George at 11:00 A.M. and the two men continue painting until the room is completed. At what time will they finish painting the room?
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
George can paint a room alone in six hours. Ed can paint the same room alone in eight hours. George starts painting at 10:00 A.M. Ed joins George at 11:00 A.M. and the two men continue painting until the room is completed. At what time will they finish painting the room?
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1/6=George's work rate
1/8=Ed's work rate
let x=hours George worked
x-1 =hours Ed worked
work done=work rate*time on job
x/6+(x-1)/8=100% =1
LCD:24
4x+3x-3=24
7x=27
x=27/7≈3.86 hrs≈3hrs+51 min
time they will finish painting the room≈1:51 pm