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Question 65120: solve
3[2x-3(4-x)]=2(1-2x)
Answer by tutorcecilia(2152)   (Show Source):
You can put this solution on YOUR website! 3[2x-3(4-x)]=2(1-2x)
3[2x-12-3x]=2-4x [use the distibutive property to multiply]
3[5x-12]=2-4x [combine like-terms]
15x-36=2-4x
15x-36=2-4x [solve for x]
15x+4x-36=2-4x+4x
19x-36+36=2+36
19x=38
x=2
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check by plugging (x=2) back into the original equation
3[2x-3(4-x)]=2(1-2x)
3[2(2)-3(4-(2)=2(1-2(2))
3(4-3(4-2)=2(1-4)
3(4-3(2))=2(-3)
3(4-6)=-6
3(-2)=-6
-6=-6 [checks out]
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