SOLUTION: how would i solve these systems -x+y+z=4 -x+2y-3z=-6 2x-4y+8z=18

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Question 651020: how would i solve these systems
-x+y+z=4
-x+2y-3z=-6
2x-4y+8z=18
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
how would i solve these systems
-x+y+z=4
-x+2y-3z=-6
2x-4y+8z=18
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I would use determinants.