SOLUTION: Can you please explain how to solve equations such as (9k+30)-(4k+10)=100 ? thanks

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Question 650938: Can you please explain how to solve equations such as (9k+30)-(4k+10)=100 ? thanks
Found 3 solutions by MathLover1, stanbon, Aaniya:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
%289k%2B30%29-%284k%2B10%29=100 first remove the parentheses,
recall:
When parentheses are preceded by a plus sign + simply remove them. Nothing changes.
When parentheses are preceded by a minus sign−change the sign of every term within the parentheses.
9k%2B30-4k-10=100

9k-4k%2B30-10=100

13k%2B20=100

13k=100-20

13k=80

k=80%2F13

k=6.1538461538461538461538461538462....round

k=6.15






Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
(9k+30)-(4k+10)=100
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9k + 30 -4k - 10 = 100
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5k +20 = 100
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5k = 80
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k = 16
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Cheers,
Stan H.
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Answer by Aaniya(63) About Me  (Show Source):
You can put this solution on YOUR website!
(9k+30)-(4k+10)=100
9k+30-4k-10=100
9k-4k+30-10=100
5k+20=100
5k=100-20
5k=80
k=80/5
k=16