SOLUTION: Solve Square root of x^2 - 3x - 6 - 3 = x - 2

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Question 65081This question is from textbook An Incremental Development
: Solve
Square root of x^2 - 3x - 6 - 3 = x - 2 This question is from textbook An Incremental Development

Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
X^2-3X-6-3=X-2
X^2-3X-X-6-3+2=0
X^2-4X-7=0 USING THE QUADRATIC EQUATION X=(-B+-SQRT[B^2-4AC])/2A WE GET
X=(4+-SQRT[16-4*1*-7])/2*1
X=(4+-SQRT[16+28])/2
X=(4+-SQRT44)/2
X=(4+-6.63)/2
X=(4+6.63)/2
X=10.63/2
X=5.315 SOLUTION
X=(4-6.63)/2
X=-2.73/2
X=-1.315 SOLUTION