x³ + 125 = 0 x³ + 5³ = 0 (x + 5)(x² - 5x + 25) = 0 x + 5 = 0; x² - 5x + 25 = 0 x = -5; x = x = x = x = x = x = x = Three solutions: -5, , Edwin
Hi, x^3+125=0 x^3 = -125 x = -5 and