SOLUTION: the perimeter of a rectangle is 46 ft the width is 3ft less than twice the length finf the length and width of the rectangle

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Question 650774: the perimeter of a rectangle is 46 ft the width is 3ft less than twice the length finf the length and width of the rectangle
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

the perimeter of a rectangle is P=46ft

the width is W 3ft less than twice the length L:

W%2B3ft=2L ....->... %28W%2B3ft%29%2F2=L

2%28L%2BW%29=46ft ....substitute L

2%28%28W%2B3ft%29%2F2%2BW%29=46ft

%28%28W%2B3ft%29%2F2%2B2W%2F2%29=46ft%2F2

%28W%2B3ft%2B2W%29%2F2=23ft

3W%2B3ft=23ft%2A2

3W%2B3ft=46ft

3W=46ft-3ft

3W=43ft

W=43ft%2F3

W=14.33ft

now find L

%2814.33ft%2B3ft%29%2F2=L

%2817.33ft%29%2F2=L

8.665ft=L