SOLUTION: Find two solutions of each equation. Give your answers in degrees (0° ≤ θ < 360°) and in radians (0 ≤ θ < 2π). Do not use a calculator. (Do not enter you
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Question 650594: Find two solutions of each equation. Give your answers in degrees (0° ≤ θ < 360°) and in radians (0 ≤ θ < 2π). Do not use a calculator. (Do not enter your answers with degree symbols.) a)sec(θ) = 2√3/3 b)sec(θ) = -2√3/3 Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! Find two solutions of each equation. Give your answers in degrees (0° ≤ θ < 360°) and in radians (0 ≤ θ < 2π). Do not use a calculator. (Do not enter your answers with degree symbols.) a)sec(θ) = 2√3/3 b)sec(θ) = -2√3/3
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a) sec(θ) = 2√3/3
cos(θ) = 3/2√3=3√3/2*3=3√3/6=√3/2
(θ)=30 and 330 deg or π/6 and 5π/6 radians (in quadrants I and IV where cos and sec>0)
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b)sec(θ) = -2√3/3
cos(θ) =-√3/2
(θ)=150 and 210 deg or 5π/6 and 7π/6 radians (in quadrants II and III where cos and sec<0)
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