SOLUTION: please help solve a box with no top is to be constructed from a piece of cardboard whose length measures 6in. more than its width. The box is to be formed by cutting squares tha

Algebra ->  Divisibility and Prime Numbers -> SOLUTION: please help solve a box with no top is to be constructed from a piece of cardboard whose length measures 6in. more than its width. The box is to be formed by cutting squares tha      Log On


   



Question 65038: please help solve
a box with no top is to be constructed from a piece of cardboard whose length measures 6in. more than its width. The box is to be formed by cutting squares that measure 2in. on each side from the four corners, and then folding up the sides. If the volume of the box will be 110in.^3 what are the dimensions of the piece of cardboard?

Answer by venugopalramana(3286) About Me  (Show Source):
You can put this solution on YOUR website!
please help solve
a box with no top is to be constructed from a piece of cardboard whose length (L SAY)measures 6in. more than its width(W SAY)
L=W+6
. The box is to be formed by cutting squares that measure 2in. on each side from the four corners,
BOX LENGTH = L-2-2=L-4 =W+6-4=W+2
BOX WIDTH = W-2-2=W-4
BOX HEIGHT=2
and then folding up the sides. If the volume of the box will be 110in.^3 what are the dimensions of the piece of cardboard?
VOLUME OF BOX = LWH =(W+2)(W-4)2=110
W^2-2W-8=55
W^2-9W+7W-63=0
W(W-9)+7(W-9)=0
(W-9)(W+7)=0
W=9
HENCE L=W+6=15
CARD BOARD SIZE = 15 X 9 INCHES