SOLUTION: y1=8x+4(7+x) y2=3(x-3)+10 and y1=y2

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Question 650180: y1=8x+4(7+x) y2=3(x-3)+10 and y1=y2
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

y1=8x+4(7+x) 

y2=3(x-3)+10 and 

y1=y2

 8x + 28 + 4x = 3x-9 + 10

      12x + 28 = 3x + 1

      9x = -27

       x = -3

and...

 8%2A-3+%2B+4%2A4+=+3%2A-6+%2B+10+=+-8