SOLUTION: On question 64722 answered by Stan which was finding the vertex of y=x^2+2x-9. I understand how to get the vertex which is (-1, -10). However, what coordinates were used to graph t
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-> SOLUTION: On question 64722 answered by Stan which was finding the vertex of y=x^2+2x-9. I understand how to get the vertex which is (-1, -10). However, what coordinates were used to graph t
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Question 64978: On question 64722 answered by Stan which was finding the vertex of y=x^2+2x-9. I understand how to get the vertex which is (-1, -10). However, what coordinates were used to graph the parabola.. Can you please show me the coordinates and explain how I get these coordinates. Thanks for your time and help.. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! On question 64722 answered by Stan which was finding the vertex of y=x^2+2x-9. I understand how to get the vertex which is (-1, -10). However, what coordinates were used to graph the parabola.. Can you please show me the coordinates and explain how I get these coordinates. Thanks for your time and help..
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f(x)=x^2+2x-9
f(0)=0^2+2*0-9
This gives you the point (0,-9)
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f(3)=3^2+2*3-9=6
This gives you the point (3,6)
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f(-3)=(-3)^2+2*(-3)-9=6
This gives you the point (-3,-6)
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Cheers,
Stan H.
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