SOLUTION: Please help me solve this quadratic equation: {{{3x^2=8x+4}}} I am in college algebra. We are learning about the zero product rule and the square root property. The direction says

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Please help me solve this quadratic equation: {{{3x^2=8x+4}}} I am in college algebra. We are learning about the zero product rule and the square root property. The direction says      Log On


   



Question 649752: Please help me solve this quadratic equation: 3x%5E2=8x%2B4
I am in college algebra. We are learning about the zero product rule and the square root property. The direction says to solve using any method.
Thank You

Found 2 solutions by solver91311, fcabanski:
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


This puppy won't factor over the rationals, so you are stuck with either completing the square or using the quadratic formula. Since you said any method and the quadratic formula is easier, that's what you get:

The two roots of are given by



For your problem (once you put it into standard form)

, , and

Plug in the numbers and simplify.

John

My calculator said it, I believe it, that settles it
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Answer by fcabanski(1391) About Me  (Show Source):
You can put this solution on YOUR website!
You can't use the square property because there is an x term.


Move all terms to one side: 3x%5E2+-+8x+-4+=+0


Use the quadratic formula x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+ where a is the coefficient of the square term, b the coefficient of the x term, and c the constant.


x+=+%288+%2B-+sqrt%28+64%2B48+%29%29%2F%286%29+ =


x+=+%288+%2B-+sqrt%28+112+%29%29%2F%286%29+ =


x+=+%288+%2B-+sqrt%28+7%2A16+%29%29%2F%286%29+=


x+=+%288+%2B-+4%2Asqrt%28+7+%29%29%2F%286%29+=


x+=+%284+%2B-+2%2Asqrt%28+7+%29%29%2F%283%29+