SOLUTION: solutions for the interval 0,2 pi sin(x)=(1)/(4sinx)

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Question 649718: solutions for the interval 0,2 pi
sin(x)=(1)/(4sinx)
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
solutions for the interval 0,2 pi
solve for x
sin(x)=(1)/(4sinx)
4sin^2x=1
sin^2x=1/4
sinx=1/2
x=π/6 and 5π/6 (in quadrants I and II where sin>0)