SOLUTION: What quantity of a 80% acid solution must be mixed with a 40% solution to produce 600 mL of a 55% solution?

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Question 649630: What quantity of a 80% acid solution must be mixed with a 40% solution to produce 600 mL of a 55% solution?
Answer by ewatrrr(24785) About Me  (Show Source):
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Hi,

What quantityhighlight%28x%29 of a 80% acid solution must be mixed with a 

40% solution to produce 600 mL of a 55% solution?

 .80x+%2B+.40%28600-x%29+=+.55%2A600

        .40x = .15*600 = 90

           x = 90/.40

           x = 225ml